JAIIB – AFB (ACCOUNTING & FINANCE FOR BANKERS)
You are given a balance sheet of a business firm with following particulars. Work out the
ratios given at the end......
Liabilities 1st yr 2nd yr
Capital 40 40
Reserves 15 20
Debentures 70 60
Other Current Liabilities 18 24
Bank Working Capital Limits 37 36
Total Liabilities 180 180
Assets 1st yr 2nd yr
Fixed Assets 32 33
Advance for fixed assets 5 -
Security Deposits 4 6
Stocks 66 81
Book Debts 49 30
Sundry Debtors 16 24
Preliminary Expenses 8 6
Total Assets 180 180
Sales 312 390
Profits 8 9
Depreciation 3 3
1. The short term sources of funds and short term uses of funds during the first year
was......
a. 55 and 131
b. 37 and 131
c. 55 and 105
d. 37 and 105
Ans - a
.............................................
2. The long term sources of funds and long term use of funds during the 2nd year
was......
a. 120 and 45
b. 100 and 45
c. 120 and 39
d. 112 and 39
Ans - d
.............................................
3. The short term sources of funds during the 2nd year, compared to the 1st year
have......
a. shown increase
b. shown decline
c. shown no change
d. none of the above
Ans - a
.............................................
4. The long term of use of funds during the 2nd year, compared to the 1st year has ......
a. shown increase
b. shown decline
c. shown no change
d. none of the above
Ans - b
.............................................
5. Current Ratio and Quick Ratio for the 2nd year are respectively......
a. 2.20:1 and 0.8:1
b. 2.42:1 and 0.9:1
c. 2.25:1 and 0.9:1
d. 2.22:1 and 0.8:1
Ans - c
.............................................
6. What is the Debt-equity ratio for the 1st and 2nd year?
a. 1.11:1 and 1.49:1
b. 1.49:1 and 1.11:1
c. 1.32:1 and 1.11:1
d. 1.98:1 and 1.73:1
Ans - d
.............................................
7. Cash accrual for 1st and 2nd year respectively is......
a. 8 and 9
b. 9 and 8
c. 11 and 12
d. 12 and 11
Ans - c
.............................................
8. Net Working Capital of 2nd year, over the 1st year has shown......
a. no change
b. deterioration
c. increase
d. decline and improvement
Ans - b
.............................................
9. Net profit to sales ratio for the 1st year has been......
a. 2.3%
b. 2.5%
c. 2.9%
d. 3.4%
Ans - b
.............................................
JAIIB-AFB-CASE STUDIES/NUMERICAL QUESTIONS
Cost of asset = 1,00,000
Estimated residual value = 10,000
Estimated useful life of asset = 5 years
Find the book value at the end of 2nd year using double declining balance method.
a. 24000
b. 36000
c. 40000
d. 64000
Ans - b
Explanation
Depreciation rate = (1/useful life) x 200%
= 1/5 x 200% = 20% x 2 = 40%
(*) depreciation stops when book value = residual value
[Year 1]
Depreciation amount for year 1
= beginning book value x depreciation rate
= 1,00,000 x 40% = 40,000
Accumulated depreciation at the end of year 1 = 40,000
Book value at the end of year 1
= 1,00,000 - 40,000 = 60,000
[Year 2]
Depreciation amount for year 2
= beginning book value x depreciation rate
= 60,000 x 40% = 24,000
Accumulated depreciation at the end of year 2
= 40,000 + 24,000 = 64,000
Book value at the end of year 2
= 1,00,000 - 64,000 = 36,000
[Year 3]
Depreciation amount for year 3
= beginning book value x depreciation rate
= 36,000 x 40% = 14,400
Accumulated depreciation at the end of year 3
= 40,000 + 24,000 + 14,400 = 78,400
Book value at the end of year 3
= 1,00,000 - 78,400 = 21,600
[Year 4]
Depreciation amount for year 4
= beginning book value x depreciation rate
= 21,600 x 40% = 8,640
Accumulated depreciation at the end of year 4
= 40,000 + 24,000 + 14,000 + 8,640 = 87,040
Book value at the end of year 4
= 1,00,000 - 87,040 = 12,960
[Year 5]
Depreciation amount for year 5
= beginning book value x depreciation rate
= 12,960 x 40% = 5,184
[NOTE]
For year 5, depreciation amount will not be 5,184.
If 5,184 is depreciated,
--> book value = 12,960 - 5,184 = 7,776
--> book value < residual value
Depreciation stops when book value = residual value
--> depreciation amount for year 5 = 2,960
--> book value = 12,960 - 2,960 = $10,000
.............................................
JAIIB-AFB-CASE STUDIES/NUMERICAL QUESTIONS
Cost of asset = 8,00,000
Estimated residual value = 10% of the cost
Estimated useful life of asset = 5 years
Find the book value at the end of 1st year using double declining balance method.
a. 240000
b. 320000
c. 480000
d. 660000
Ans - c
Explanation
Depreciation rate = (1/useful life) x 200%
= 1/5 x 200% = 20% x 2 = 40%
[Year 1]
Depreciation amount for year 1
= beginning book value x depreciation rate
8,00,000 x 40% = 3,20,000
Accumulated depreciation at the end of year 1 = 3,20,000
Book value at the end of year 1
8,00,000 - 3,20,000 = 4,80,000
.............................................
Cost of asset = 8,00,000
Estimated residual value = 10% of the cost
Estimated useful life of asset = 5 years
Find the accumulated depreciation for the 2nd year using double declining balance
method.
a. 312000
b. 424000
c. 512000
d. 604000
Ans - c
Explanation
Depreciation rate = (1/useful life) x 200%
= 1/5 x 200% = 20% x 2 = 40%
[Year 1]
Depreciation amount for year 1
= beginning book value x depreciation rate
8,00,000 x 40% = 3,20,000
Accumulated depreciation at the end of year 1 = 3,20,000
Book value at the end of year 1
8,00,000 - 3,20,000 = 4,80,000
[Year 2]
Depreciation amount for year 2
= beginning book value x depreciation rate
4,80,000 x 40% = 1,92,000
Accumulated depreciation at the end of year 2
3,20,000 + 1,92,000 = 5,12,000
.............................................
Cost of asset = 8,00,000
Estimated residual value = 10% of the cost
Estimated useful life of asset = 5 years
Find the book value at the end of 1st year using double declining balance method.
a. 240000
b. 320000
c. 480000
d. 660000
Ans - c
Explanation
Depreciation rate = (1/useful life) x 200%
= 1/5 x 200% = 20% x 2 = 40%
[Year 1]
Depreciation amount for year 1
= beginning book value x depreciation rate
8,00,000 x 40% = 3,20,000
Accumulated depreciation at the end of year 1 = 3,20,000
Book value at the end of year 1
8,00,000 - 3,20,000 = 4,80,000
[Year 2]
Depreciation amount for year 2
= beginning book value x depreciation rate
4,80,000 x 40% = 1,92,000
Accumulated depreciation at the end of year 2
3,20,000 + 1,92,000 = 5,12,000
Book value at the end of year 2
8,00,000 - 5,12,000 = 2,88,000
2,88,000 x 40% = 1,15,200
5,12,000 + 1,15,200 = 6,27,200
8,00,000 - 6,27,000 = 1,72,800
1,72,800 x 40% = 69,120
6,27,200 + 69,120 = 6,96,320
8,00,000 - 6,96,320 = 1,03,680
1,03,680 - 80,000 = 23,680
6,96,320 + 23,680 = 7,20,000
8,00,000 - 7,20,000 = 80,000
.............................................
JAIIB-AFB-CASE STUDIES/NUMERICAL QUESTIONS
Sahil took a loan for 6 years at the rate of 5% per annum on Simple Interest, If the total
interest paid was Rs. 1230, the principal was
A. 4100
B. 4200
C. 4300
D. 4400
Ans - A
Explanation:
S.I.=P*R*T/100
=>P=S.I.*100/R/T
By applying above formula we can easily solve this question, as we are already having
the simple interest.
P = 1230*100/6/5
= 4100
.............................................
There was simple interest of Rs. 4016.25 on a principal amount at the rate of 9%p.a. in
5 years. Find the principal amount
A. Rs 7925
B. Rs 8925
C. Rs 7926
D. Rs 7925
Ans - B
Explanation:
S.I.=P*R*T/100
=>P=S.I.*100/R/T
P = 4016.25*100/9/5
= 8925
.............................................
Effective annual rate of interest corresponding to nominal rate of 6% per annum
compounded half yearly will be
A. 6.09%
B. 6.10%
C. 6.12%
D. 6.14%
Ans - A
Explanation:
Let the amount Rs 100 for 1 year when compounded half yearly, n = 2, Rate = 6/2 =
3%
Amount=100(1+3/100)^2=106.09
Effective rate = (106.09 - 100)% = 6.09%
.............................................
A sum of money invested at compound interest to Rs. 800 in 3 years and to Rs 840 in 4
years. The rate on interest per annum is.
A. 4%
B. 5%
C. 6%
D. 7%
Ans - B
Explanation:
S.I. on Rs 800 for 1 year = 40
Rate = (100*40)/(800*1) = 5%
.............................................
Find the rate at Simple interest, at which a sum becomes four times of itself in 15 years.
A. 10%
B. 20%
C. 30%
D. 40%
Ans - B
Explanation:
Let sum be x and rate be r%
then, (x*r*15)/100 = 3x [important to note here is that simple interest will be 3x not 4x,
beause 3x+x = 4x]
=> r = 20%
.............................................
At 5% per annum simple interest, Rahul borrowed Rs. 500. What amount will he pay to
clear the debt after 4 years ?
A. 750
B. 700
C. 650
D. 600
Ans - D
Explanation:
We need to calculate the total amount to be paid by him after 4 years, So it will be
Principal + simple interest. So,
=>500+500*5*4/100
=>Rs.600
.............................................
A sum of money amounts to Rs 9800 after 5 years and Rs 12005 after 8 years at the
same rate of simple interest. The rate of interest per annum is ......
a. 9%
b. 10%
c. 11%
d. 12%
Ans - d
Explanation:
We can get SI of 3 years = 12005 - 9800 = 2205
SI for 5 years = (2205/3)*5 = 3675 [so that we can get principal amount after deducting
SI]
Principal = 12005 - 3675 = 6125
So Rate = (100*3675)/(6125*5) = 12%
.............................................
JAIIB-AFB-CASE STUDIES/NUMERICAL QUESTIONS
A man saves Rs 200 at the end of each year and lends the money at 5% compound
interest. How much will it become at the end of 3 years?
a. Rs 660
b. Rs 662
c. Rs 664
d. Rs 666
Ans- b
Explanation:
= [200(2120×2120×2120)+200(2120×2120)+200(2120)]
= 662